Math Help... PLEASE

Alive

Building and living.
Jan 14, 2011
39
4
0
www.everythingforever.info
(Use the following information to answer questions 3 through 6). Suppose that in the manufacture of a particular product that there are two critical dimensions: (1) the length of the item, and (2) the width of the item. From past experience it is known that 5 percent of the items produced will not meet the length requirement. Past records also indicate that 3 percent of the items will not meet the width requirement. Assume that there are no dependencies between the length and width of the manufactured items. (Round your answers to 4 decimal places)

3. What is the probability that an item will meet at least one of the two dimension requirements?

4. What is the probability that an item will meet neither of the two dimension requirements?

5. What is the probability that an item will meet both of the two dimension requirements?

6. What is the probability that an item will meet only the length requirement?

(Hint: The probability that an item meets the length requirement AND NOT the width requirement.)

I DON'T EVEN KNOW WHERE TO START WITH THIS.

Halp, please.
 


Just convert everything to numbers and play around with.

Start with the question. I'm gona use an apostrophe to dictate a messing up the requirements.

P'(L) = 5/100
P'(W) = 3/100

So the probability of getting the proper specification (not fucking it up) would be 1-P':
P(L) = 95/100
P(W) = 97/100

3. One of 2 dimensions. Think of it like programming.
P(L or W) = P(L) + P(W) - P(L and W) = 95/100 + 97/100 - ((95x97)/(100^2)) = 0.9985

so answer is 99.85%

Alright too lazy to do the rest. But if you get that the rest should be a breeze.
 
Just convert everything to numbers and play around with.

Start with the question. I'm gona use an apostrophe to dictate a messing up the requirements.

P'(L) = 5/100
P'(W) = 3/100

So the probability of getting the proper specification (not fucking it up) would be 1-P':
P(L) = 95/100
P(W) = 97/100

3. One of 2 dimensions. Think of it like programming.
P(L or W) = P(L) + P(W) - P(L and W) = 95/100 + 97/100 - ((95x97)/(100^2)) = 0.9985

so answer is 99.85%

Alright too lazy to do the rest. But if you get that the rest should be a breeze.

Thanks! It makes sense now. I guess I just needed it to be simplified.

To the poster above you, thanks for figuring the answers out. Much appreciated!

To the poster below you and above me, it's Quantitative Analysis 235, a course I have to get through to get my Accounting degree.
 
Thanks! It makes sense now. I guess I just needed it to be simplified.

To the poster above you, thanks for figuring the answers out. Much appreciated!

To the poster below you and above me, it's Quantitative Analysis 235, a course I have to get through to get my Accounting degree.

Well good luck passing 235, you're gonna need it!